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Chapter 8 β€” Periodic Functions

Sine and cosine aren’t just about triangles β€” they are the building blocks of periodic phenomena: sound waves, alternating current, tidal patterns, seasonal temperatures, and even the motion of a Ferris wheel. This chapter teaches you to graph all six trig functions and their transformations, and introduces inverse trigonometric functions for solving equations.


Table of Contents


Glossary

Term Definition
Periodic function A function that repeats its values at regular intervals: $f(x + P) = f(x)$
Period ($P$) The smallest positive value such that $f(x + P) = f(x)$ for all $x$
Amplitude Half the distance between the maximum and minimum: $|a|$ in $y = a\sin(bx)$
Midline The horizontal line halfway between max and min: $y = d$ in $y = a\sin(bx - c) + d$
Phase shift The horizontal displacement: $\dfrac{c}{b}$ in $y = a\sin(bx - c) + d$
Frequency Number of cycles per unit: $f = 1/P$
$\sin^{-1}(x)$ / $\arcsin(x)$ Inverse sine; returns angle in $[-\pi/2, \pi/2]$
$\cos^{-1}(x)$ / $\arccos(x)$ Inverse cosine; returns angle in $[0, \pi]$
$\tan^{-1}(x)$ / $\arctan(x)$ Inverse tangent; returns angle in $(-\pi/2, \pi/2)$

1 β€” Graphs of Sine and Cosine

1.1 The Basic Sine Graph

$y = \sin x$ has these properties:

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | $(-\infty, \infty)$ | | Range | $[-1, 1]$ | | Period | $2\pi$ | | Amplitude | $1$ | | $x$-intercepts | $x = n\pi$ for integer $n$ | | Maximum | $y = 1$ at $x = \dfrac{\pi}{2} + 2n\pi$ | | Minimum | $y = -1$ at $x = \dfrac{3\pi}{2} + 2n\pi$ | | Symmetry | Odd ($\sin(-x) = -\sin x$); origin symmetry |

Key points for one period $[0, 2\pi]$:

$(0, 0) \to \left(\dfrac{\pi}{2}, 1\right) \to (\pi, 0) \to \left(\dfrac{3\pi}{2}, -1\right) \to (2\pi, 0)$

1.2 The Basic Cosine Graph

$y = \cos x$ has these properties:

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | $(-\infty, \infty)$ | | Range | $[-1, 1]$ | | Period | $2\pi$ | | Amplitude | $1$ | | Maximum | $y = 1$ at $x = 2n\pi$ | | Minimum | $y = -1$ at $x = \pi + 2n\pi$ | | Symmetry | Even ($\cos(-x) = \cos x$); $y$-axis symmetry |

Key points for one period $[0, 2\pi]$:

$(0, 1) \to \left(\dfrac{\pi}{2}, 0\right) \to (\pi, -1) \to \left(\dfrac{3\pi}{2}, 0\right) \to (2\pi, 1)$

Relationship: $\cos x = \sin!\left(x + \dfrac{\pi}{2}\right)$. The cosine graph is the sine graph shifted left by $\dfrac{\pi}{2}$.

1.3 Amplitude

Amplitude $= a $ in $y = a\sin(bx)$ or $y = a\cos(bx)$.

It measures the height from the midline to the peak (or trough).

  • $ a > 1$: vertical stretch (taller waves)
  • $0 < a < 1$: vertical compression (shorter waves)
  • $a < 0$: reflection over the $x$-axis (flipped)

1.4 Period

Period $= \dfrac{2\pi}{ b }$ in $y = a\sin(bx)$ or $y = a\cos(bx)$.
  • $ b > 1$: horizontal compression (shorter period, faster oscillation)
  • $0 < b < 1$: horizontal stretch (longer period, slower oscillation)

Example: $y = 3\sin(2x)$.

Amplitude $= 3 = 3$. Period $= \dfrac{2\pi}{2} = \pi$.

The wave oscillates between $-3$ and $3$, completing a full cycle every $\pi$ units.

1.5 The General Sinusoidal Function

\[y = a\sin(bx - c) + d \qquad \text{or} \qquad y = a\cos(bx - c) + d\]

| Parameter | Effect | Formula | |———–|——–|β€”β€”β€”| | $a$ | Amplitude | $|a|$ | | $b$ | Period | $P = \dfrac{2\pi}{|b|}$ | | $c$ | Phase shift | $\dfrac{c}{b}$ (right if positive) | | $d$ | Vertical shift / Midline | $y = d$ |

1.6 Phase Shift (Horizontal Shift)

Phase Shift $= \dfrac{c}{b}$ in $y = a\sin(bx - c) + d$.

Factor out $b$: $y = a\sin!\left[b!\left(x - \dfrac{c}{b}\right)\right] + d$

The graph shifts right by $\dfrac{c}{b}$ if $c > 0$, or left if $c < 0$.

Example: $y = \sin!\left(2x - \dfrac{\pi}{3}\right)$.

Phase shift $= \dfrac{\pi/3}{2} = \dfrac{\pi}{6}$ to the right.

Period $= \dfrac{2\pi}{2} = \pi$.

The starting point shifts from $x = 0$ to $x = \dfrac{\pi}{6}$.

1.7 Vertical Shift (Midline)

The constant $d$ shifts the entire graph up or down. The midline is $y = d$ (the horizontal line the wave oscillates around).

  • Maximum value: $d + a $
  • Minimum value: $d - a $

Example: $y = -2\cos(x) + 3$.

Amplitude: $ -2 = 2$. Midline: $y = 3$. Reflection (since $a < 0$).

Max: $3 + 2 = 5$ (but at the usual cosine minimum positions because of reflection). Min: $3 - 2 = 1$.

1.8 Graphing Strategy

  1. Identify $a$, $b$, $c$, $d$.
  2. Compute amplitude $= a $, period $= 2\pi/ b $, phase shift $= c/b$, midline $= d$.
  3. Find the starting point (phase shift) and ending point (phase shift + period).
  4. Divide the period into four equal parts to locate the quarter-points.
  5. Plot the five key points (start, quarter, half, three-quarter, end) using sine or cosine pattern.
  6. Apply reflection if $a < 0$.
  7. Extend the pattern in both directions.

Example: Graph $y = 3\sin!\left(\dfrac{\pi}{2}x - \pi\right) + 1$.

$a = 3$, $b = \dfrac{\pi}{2}$, $c = \pi$, $d = 1$.

  • Amplitude: $3$
  • Period: $\dfrac{2\pi}{\pi/2} = 4$
  • Phase shift: $\dfrac{\pi}{\pi/2} = 2$ (right)
  • Midline: $y = 1$

Five key points (starting at $x = 2$, period $= 4$, so quarter $= 1$):

| $x$ | $y$ | |β€”|β€”| | $2$ | $1$ (midline, going up) | | $3$ | $4$ (max: $1 + 3$) | | $4$ | $1$ (midline, going down) | | $5$ | $-2$ (min: $1 - 3$) | | $6$ | $1$ (midline, one full cycle) |


2 β€” Graphs of the Other Trigonometric Functions

2.1 The Tangent Function

$y = \tan x = \dfrac{\sin x}{\cos x}$

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | All reals except $x = \dfrac{\pi}{2} + n\pi$ | | Range | $(-\infty, \infty)$ | | Period | $\pi$ | | Vertical asymptotes | $x = \dfrac{\pi}{2} + n\pi$ | | $x$-intercepts | $x = n\pi$ | | Symmetry | Odd (origin symmetry) | | Behavior | Increasing on each branch |

Key points in one period $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$:

$\left(-\dfrac{\pi}{4}, -1\right)$, $(0, 0)$, $\left(\dfrac{\pi}{4}, 1\right)$

Transformed tangent: $y = a\tan(bx - c) + d$

  • Period $= \dfrac{\pi}{ b }$
  • Phase shift $= \dfrac{c}{b}$
  • Vertical stretch by $ a $; vertical shift $d$

Tangent has no amplitude β€” its range is all real numbers. The parameter $a$ controls the vertical stretch (steepness), not a bounded amplitude.

2.2 The Cotangent Function

$y = \cot x = \dfrac{\cos x}{\sin x}$

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | All reals except $x = n\pi$ | | Range | $(-\infty, \infty)$ | | Period | $\pi$ | | Vertical asymptotes | $x = n\pi$ | | $x$-intercepts | $x = \dfrac{\pi}{2} + n\pi$ | | Symmetry | Odd | | Behavior | Decreasing on each branch |

Cotangent is like tangent’s mirror image β€” it decreases where tangent increases.

2.3 The Secant Function

$y = \sec x = \dfrac{1}{\cos x}$

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | All reals except $x = \dfrac{\pi}{2} + n\pi$ | | Range | $(-\infty, -1] \cup [1, \infty)$ | | Period | $2\pi$ | | Vertical asymptotes | $x = \dfrac{\pi}{2} + n\pi$ (where $\cos x = 0$) | | No $x$-intercepts | (secant is always $\ge 1$ or $\le -1$) | | Symmetry | Even |

Graphing secant from cosine: Draw the cosine curve lightly. The secant graph has U-shaped branches opening away from the $x$-axis, with vertices at the max/min of cosine, and vertical asymptotes where cosine crosses zero.

2.4 The Cosecant Function

$y = \csc x = \dfrac{1}{\sin x}$

| Property | Value | |β€”β€”β€”-|β€”β€”-| | Domain | All reals except $x = n\pi$ | | Range | $(-\infty, -1] \cup [1, \infty)$ | | Period | $2\pi$ | | Vertical asymptotes | $x = n\pi$ (where $\sin x = 0$) | | Symmetry | Odd |

Graph cosecant the same way as secant β€” draw sine lightly, then draw U-branches at each peak/trough, with asymptotes at sine’s zeros.


3 β€” Inverse Trigonometric Functions

3.1 Why We Need Restricted Domains

Sine, cosine, and tangent are not one-to-one over their full domains (they fail the horizontal line test). To define an inverse, we restrict the domain to an interval where the function is one-to-one.

3.2 Inverse Sine (Arcsine)

Inverse Sine: $y = \sin^{-1}(x) = \arcsin(x)$

β€œWhat angle in $\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$ has sine equal to $x$?”

Property Value
Domain $[-1, 1]$
Range $\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$

\(\sin^{-1}(x) = \theta \iff \sin\theta = x \text{ and } -\frac{\pi}{2} \le \theta \le \frac{\pi}{2}\)

| Expression | Answer | Reasoning | |β€”|β€”|β€”| | $\sin^{-1}(1)$ | $\dfrac{\pi}{2}$ | $\sin\dfrac{\pi}{2} = 1$ | | $\sin^{-1}!\left(\dfrac{1}{2}\right)$ | $\dfrac{\pi}{6}$ | $\sin\dfrac{\pi}{6} = \dfrac{1}{2}$ | | $\sin^{-1}!\left(-\dfrac{\sqrt{2}}{2}\right)$ | $-\dfrac{\pi}{4}$ | $\sin!\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$ | | $\sin^{-1}(0)$ | $0$ | $\sin 0 = 0$ |

3.3 Inverse Cosine (Arccosine)

Inverse Cosine: $y = \cos^{-1}(x) = \arccos(x)$

β€œWhat angle in $[0, \pi]$ has cosine equal to $x$?”

Property Value
Domain $[-1, 1]$
Range $[0, \pi]$

\(\cos^{-1}(x) = \theta \iff \cos\theta = x \text{ and } 0 \le \theta \le \pi\)

| Expression | Answer | |β€”|β€”| | $\cos^{-1}(0)$ | $\dfrac{\pi}{2}$ | | $\cos^{-1}!\left(-\dfrac{1}{2}\right)$ | $\dfrac{2\pi}{3}$ | | $\cos^{-1}(1)$ | $0$ | | $\cos^{-1}(-1)$ | $\pi$ |

3.4 Inverse Tangent (Arctangent)

Inverse Tangent: $y = \tan^{-1}(x) = \arctan(x)$

β€œWhat angle in $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$ has tangent equal to $x$?”

Property Value
Domain $(-\infty, \infty)$
Range $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$
Horizontal asymptotes $y = -\dfrac{\pi}{2}$ and $y = \dfrac{\pi}{2}$

\(\tan^{-1}(x) = \theta \iff \tan\theta = x \text{ and } -\frac{\pi}{2} < \theta < \frac{\pi}{2}\)

| Expression | Answer | |β€”|β€”| | $\tan^{-1}(1)$ | $\dfrac{\pi}{4}$ | | $\tan^{-1}(-1)$ | $-\dfrac{\pi}{4}$ | | $\tan^{-1}(0)$ | $0$ | | $\tan^{-1}(\sqrt{3})$ | $\dfrac{\pi}{3}$ |

3.5 Composing Trig and Inverse Trig Functions

Cancellation Properties:

\(\sin(\sin^{-1}(x)) = x \quad \text{for } x \in [-1, 1]\) \(\sin^{-1}(\sin(x)) = x \quad \text{for } x \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\)

Same pattern for cosine and tangent with their respective restricted ranges.

Outside the restricted range, the inverse doesn’t simply β€œcancel”:

$\sin^{-1}!\left(\sin\dfrac{5\pi}{6}\right) \ne \dfrac{5\pi}{6}$ because $\dfrac{5\pi}{6} \notin \left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$.

Instead: $\sin\dfrac{5\pi}{6} = \dfrac{1}{2}$, so $\sin^{-1}!\left(\dfrac{1}{2}\right) = \dfrac{\pi}{6}$.

Example: Evaluate $\cos!\left(\sin^{-1}!\left(\dfrac{3}{5}\right)\right)$.

Let $\theta = \sin^{-1}!\left(\dfrac{3}{5}\right)$, so $\sin\theta = \dfrac{3}{5}$ with $\theta \in$ Q I.

$\cos\theta = \sqrt{1 - \sin^2\theta} = \sqrt{1 - \dfrac{9}{25}} = \sqrt{\dfrac{16}{25}} = \dfrac{4}{5}$

Answer: $\dfrac{4}{5}$

Example: Evaluate $\tan!\left(\cos^{-1}!\left(-\dfrac{5}{13}\right)\right)$.

Let $\theta = \cos^{-1}!\left(-\dfrac{5}{13}\right)$, so $\cos\theta = -\dfrac{5}{13}$ with $\theta \in$ Q II (since cosine is negative and $\theta \in [0, \pi]$).

$\sin\theta = \sqrt{1 - \dfrac{25}{169}} = \sqrt{\dfrac{144}{169}} = \dfrac{12}{13}$ (positive in Q II)

$\tan\theta = \dfrac{12/13}{-5/13} = -\dfrac{12}{5}$


Key Takeaways

  1. Sine and cosine are periodic with period $2\pi$, amplitude $1$, range $[-1, 1]$.
  2. General form: $y = a\sin(bx - c) + d$ β†’ amplitude $ a $, period $2\pi/ b $, phase shift $c/b$, midline $y = d$.
  3. Five-point method: Divide one period into quarters to plot sine/cosine efficiently.
  4. Tangent and cotangent have period $\pi$, range $(-\infty, \infty)$, and vertical asymptotes.
  5. Secant and cosecant are reciprocals of cosine and sine β€” graph them using the parent function’s curve.
  6. Inverse trig functions restrict the domain to produce a one-to-one function:
    • $\sin^{-1}$: range $[-\pi/2, \pi/2]$
    • $\cos^{-1}$: range $[0, \pi]$
    • $\tan^{-1}$: range $(-\pi/2, \pi/2)$
  7. Composition caution: $\sin^{-1}(\sin x) = x$ only when $x$ is in the restricted range.

Practice Questions

Q1. Find the amplitude, period, phase shift, and midline of $y = -4\cos!\left(3x + \dfrac{\pi}{2}\right) + 2$.

Answer:
$a = -4$, $b = 3$, $c = -\dfrac{\pi}{2}$, $d = 2$.

  • Amplitude: $ -4 = 4$
  • Period: $\dfrac{2\pi}{3}$
  • Phase shift: $\dfrac{-\pi/2}{3} = -\dfrac{\pi}{6}$ (left $\dfrac{\pi}{6}$)
  • Midline: $y = 2$
  • Max: $2 + 4 = 6$, Min: $2 - 4 = -2$

Q2. Write the equation of a sine function with amplitude 5, period $4\pi$, phase shift $\pi$ to the right, and midline $y = -3$.

Answer:
$|a| = 5 \Rightarrow a = 5$

$P = \dfrac{2\pi}{b} = 4\pi \Rightarrow b = \dfrac{1}{2}$

Phase shift $= \dfrac{c}{b} = \pi \Rightarrow c = \dfrac{\pi}{2}$

\(y = 5\sin\!\left(\frac{1}{2}x - \frac{\pi}{2}\right) - 3\)

Q3. Find the period and asymptotes of $y = \tan!\left(\dfrac{\pi}{4}x\right)$.

Answer:
Period $= \dfrac{\pi}{\pi/4} = 4$

Asymptotes: $\dfrac{\pi}{4}x = \dfrac{\pi}{2} + n\pi \Rightarrow x = 2 + 4n$

First few: $x = -2, 2, 6, 10, \ldots$

Q4. Evaluate: $\cos^{-1}!\left(-\dfrac{\sqrt{3}}{2}\right)$.

Answer:
Need $\theta \in [0, \pi]$ with $\cos\theta = -\dfrac{\sqrt{3}}{2}$.

Reference angle: $\dfrac{\pi}{6}$ (since $\cos\dfrac{\pi}{6} = \dfrac{\sqrt{3}}{2}$). In Q II: $\theta = \pi - \dfrac{\pi}{6} = \dfrac{5\pi}{6}$.

Q5. Evaluate: $\sin!\left(\tan^{-1}!\left(\dfrac{7}{24}\right)\right)$.

Answer:
Let $\theta = \tan^{-1}!\left(\dfrac{7}{24}\right)$, so $\tan\theta = \dfrac{7}{24}$ with $\theta$ in Q I.

Right triangle: opposite $= 7$, adjacent $= 24$, hypotenuse $= \sqrt{49 + 576} = \sqrt{625} = 25$.

$\sin\theta = \dfrac{7}{25}$

Q6. Evaluate: $\sin^{-1}!\left(\sin\dfrac{7\pi}{6}\right)$.

Answer:
$\sin\dfrac{7\pi}{6} = -\dfrac{1}{2}$ (Q III, reference angle $\dfrac{\pi}{6}$).

$\sin^{-1}!\left(-\dfrac{1}{2}\right) = -\dfrac{\pi}{6}$ (must be in $[-\pi/2, \pi/2]$).

Answer: $-\dfrac{\pi}{6}$


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